# Writing Ionic Equation of the Reactions of Acids

Steps in writing the ionic equation of the reactions of acids:

1. Write the chemical equation of the reaction.
2. List down all the ion presence below the equation.
3. Cancel the ions that do not change in the reaction.
4. Rewrite the equation with only the ions that have changed in the reaction.

Example

Write the ionic equations for the following reactions:
a. Acids + Zinc
b. Acids + Metal Carbonate
c. Acids + Base Oxide
d. Acids + Alkali

a. Acids + Zinc
We can use any acid for the reaction, as it will not affect the ionic equation at the end.
In this case, let's use hydrochloric acid for the chemical equation.

Step 1: Writing the Chemical Equation
$2HCl+Zn→ZnC l 2 + H 2$
Step 2: List down the ions
$2 H + +2C l − +Zn→Z n 2+ +2C l − + H 2$
Step 3: Cancel the ions that do not change
$2 H + + 2C l − +Zn→Z n 2+ + 2C l − + H 2$
Step 4: Rewrithe the equation
$2 H + +Zn→Z n 2+ + H 2$
b. Acids + Metal Carbonate
Let's use hydrochloric acid and calcium carbonate
Step 1:
$2HCl+CaC O 3 →CaC l 2 +C O 2 + H 2 O$
Step 2:
$2 H + +2C l − +C a 2+ +C O 3 2− →C a 2+ +2C l − +C O 2 + H 2 O$
Step 3:
$2 H + + 2C l − + C a 2+ +C O 3 2− → C a 2+ + 2C l − +C O 2 + H 2 O$
Step 4:
$2 H + +C O 3 2− →C O 2 + H 2 O$
c. Acids + Base Oxide
Let's use Hydrochloric acid and Zinc Oxide
Step 1:
$2HCl+ZnO→ZnC l 2 + H 2 O$
Step 2:
$2 H + +2C l − +Z n 2+ + O 2− →Z n 2+ +2C l − + H 2 O$
Step 3:
$2 H + + 2C l − + Z n 2+ + O 2− → Z n 2+ + 2C l − + H 2 O$
Step 4:
$2 H + + O 2− → H 2 O$
d. Acids + Alkali
Step 1:
$HCl+NaOH→NaCl+ H 2 O$
Step 2:
$H + +C l − +N a + +O H − →N a + +C l − + H 2 O$
Step 3:
$H + + C l − + N a + +O H − → N a + + C l − + H 2 O$
Step 4:
$H + +O H − → H 2 O$